1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wel
3 years ago
5

What inequality does the red graph show?

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0
X= or > 2

You would write that as > with a line under it.

The dot is closed meaning that it can be equal to that value.

It points in the right direction meaning all values greater than the value.

Therefore it can be equal to or greater than the value, 2.

Tresset [83]3 years ago
6 0
It's either equal to or greater than 2
You might be interested in
Right answer will get a brainlist.
AlexFokin [52]

Answer:

blooooooop

Step-by-step explanation:

6 left and 5 up

3 0
3 years ago
An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f
Sphinxa [80]

Answer:

Distance between plane and airport is 134.4 miles.

Step-by-step explanation:

Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.

To find : How far is the plane from the airport.

Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south  and angle form is S 49.17° W

Refer the attached picture for clearance.

Applying law of cosines

c^2=a^2+b^2-2ab Cos(C)

c=\sqrt{a^2+b^2-2ab Cos(C)}

where a= 150 miles

b=170 miles

C=   49.17° angle in degree

c = distance between plane from the airport

Put values in the formula,

c=\sqrt{a^2+b^2-2ab Cos(C)}

c=\sqrt{150^2+170^2-2(150)(170) Cos(49.17^{\circ})}

c=\sqrt{22500+28900-51000(0.653)}

c=\sqrt{51400-33303}

c=\sqrt{18057}

c=134.37

Therefore, Distance between plane and airport is 134.4 miles.

5 0
3 years ago
Read 2 more answers
The function y = –0.296x2 + 2.7x models the length x and height y that your sister's pet rabbit can jump, in centimeters. How hi
Ne4ueva [31]
To figure out the solution in a problem related to calculate maximum or minimum of something, you've to derive the involved equation, and make it equal to 0, solving the x.

So:
y = -0'296x² + 2'7x
y' = -0'592x + 2'7
0 = <span>-0'592x + 2'7
</span><span>-0'592x = 2'7
</span>x = 4'56

And if we substitute 4'56 on the first equation:
y = -0'296·<span>4'56² + 2'7·4'56
y = 6'16

So the length of the jump is 4'56cm, and the height 6'16cm.</span>
8 0
4 years ago
Read 2 more answers
(-2)(7)(-75)(3)(-2)=?
Serhud [2]
Equals -6300 fjesshehw
5 0
3 years ago
Read 2 more answers
What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.
Anna007 [38]

Answer:

-  \frac{5}{2}

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

y =  \frac{2}{5} x - 4

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

=  - 1 \div  \frac{2}{5}

=  - 1 \times  \frac{5}{2}

=  -  \frac{5}{2}

5 0
3 years ago
Other questions:
  • Ivan runs 7 miles in 60 minutes. at the same rate how many miles would he run in 24 minutes
    10·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%7B%286%20-%202%29%7D%5E%7B2%7D%20" id="TexFormula1" title=" {(6 - 2)}^{2} " alt=" {(6 - 2)
    11·2 answers
  • 8 yd 2 ft + 9 yd 1ft
    13·2 answers
  • Find the quotient.<br>5)85<br>​
    11·1 answer
  • Write the expression in complete factored form.<br> 2u(p + 7) + 3(p + 7) =
    6·1 answer
  • Find the volume of the composite figure. Round to the nearest hundredth
    10·2 answers
  • I need help! Can someone pls help with this?
    8·2 answers
  • Please help out . I do not understand this whatsoever.
    9·1 answer
  • How many times does 2/3 go into 7 1/3
    13·2 answers
  • Help with this math test
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!