Answer:
blooooooop
Step-by-step explanation:
6 left and 5 up
Answer:
Distance between plane and airport is 134.4 miles.
Step-by-step explanation:
Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.
To find : How far is the plane from the airport.
Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south and angle form is S 49.17° W
Refer the attached picture for clearance.
Applying law of cosines


where a= 150 miles
b=170 miles
C= 49.17° angle in degree
c = distance between plane from the airport
Put values in the formula,






Therefore, Distance between plane and airport is 134.4 miles.
To figure out the solution in a problem related to calculate maximum or minimum of something, you've to derive the involved equation, and make it equal to 0, solving the x.
So:
y = -0'296x² + 2'7x
y' = -0'592x + 2'7
0 = <span>-0'592x + 2'7
</span><span>-0'592x = 2'7
</span>x = 4'56
And if we substitute 4'56 on the first equation:
y = -0'296·<span>4'56² + 2'7·4'56
y = 6'16
So the length of the jump is 4'56cm, and the height 6'16cm.</span>
Answer:

Step-by-step explanation:
4x -10y= 40
Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.
10y= 4x -40
Divide both side by 10:

The product of the gradients of perpendicular lines is -1.
⅖(gradient of line)= -1
Gradient of perpendicular line


