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never [62]
3 years ago
9

What are the three ratios for 18:4

Mathematics
2 answers:
aniked [119]3 years ago
8 0
9:2 27:6 36:8 here are the three ratios
s344n2d4d5 [400]3 years ago
6 0
9:2, 36:8, 72:16
Ratios
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NEED HELP ASAP ILL MARK BRAINLIEST IF ITS RIGHT!!!​
Leto [7]

Answer:

f(1)=-11

f(n)=f(n-1)+22

Step-by-step explanation:

Base equation:

f(n)=-11+22(n-1)

f(1)=-11+22(1-1)

f(1)=-11+0

f(1)=-11

f(n)=-33+22n

f(n-1)=-11+22(n-2)

f(n-1)=-55+22n

-33+22n=-55+22n+x

22n gets canceled out

-33=-55+x

-33+55=x

x=22

f(n)=f(n-1)+22

5 0
3 years ago
Find the sum of the first 21 terms of the sequence 5,9, 13, 17, 21, ...
Scorpion4ik [409]
21(5+85)/2= 21•45= 945
8 0
3 years ago
A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

Thus 2 \times 10^{19} times more stars are there in universe compared to human eye can see

5 0
3 years ago
5 9/16<br> As an Improper fraction
evablogger [386]

Answer:

89/16

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Can somebody help me with this pleaseee
AysviL [449]

Answer:

lesser x = -4.73205, so -4.73

greater x = -1.26795, so -1.27

7 0
2 years ago
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