Question

The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 0.6. Approximately how many times the variability in the heights of the seventh graders is the variability in the heights of the sixth graders? (Round all values to the tenths place.) 0.3 1.2 1.7 2.0

Answer 1

The correct answer is that the variability is 2.0 times as large.

In the first set, the MAD is 1.2.

In the second set, the MAD is 0.6.

Dividing 1.2 by 0.6 gives us a factor of 2.

Answer 2

Answer:

The correct answer is option D

Step-by-step explanation:

The variability in the heights of the seventh graders to the variability in the heights of the sixth graders can be determined by taking the ratios of the MAD of the two sets of data

$\frac{MAD1}{MAD2} \\= \frac{1.2}{0.6} \\= 2.0$