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2 years ago

A t-shirt increased in price by 1/4. After the increase it was £20. What was the original price of the t-shirt?

Mathematics

1 answer:

Licemer1 [7]2 years ago

8 0

Answer:

£16

the t-shirt increased by 0.25. let's convert that to percentage

therefore it increased by 25%

By using cross multiplication we can write as follows:

125%=£20

100%=£ x

(100×20)/125= £16

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(-10) to the negitive 4 power

SIZIF [17.4K]

$(-10)^{-4}=\\
\left(-\frac{1}{10}\right)^4=\\
\frac{1}{10000}
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3 years ago

Someone plz answer this for me

pishuonlain [190]

Answer:

Step-by-step explanation:

D= $\sqrt{(1-(-5))^2+(4-(-4)^2}$

D= $\sqrt{6^2+8^2}$

D= $\sqrt{36+64}$

D= $\sqrt{100}$

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3 years ago

10 squares and 8 circles. What is the simplest ratio of circles to total shapes?

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the surface area of the surface given by the portion of the paraboloid z=3x2+3y2 that lies inside the cylinder x2+y2=4. (hi

natta225 [31]

Parameterize the part of the paraboloid within the cylinder - I'll call it $S$ - by

$\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\left\langle u\cos v,u\sin v,3u^2\right\rangle$

with $0\le u\le2$ and $0\le v\le2\pi$ . The region's area is given by the surface integral

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=2}\int_{v=0}^{v=2\pi}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du\,\mathrm dv$
$=\displaystyle2\pi\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du$

Take $w=1+36u^2$ so that $\mathrm dw=72u\,\mathrm du$ , and the integral becomes

$=\displaystyle\frac{2\pi}{72}\int_{w=1}^{w=145}\sqrt w\,\mathrm dw$
$=\displaystyle\frac\pi{36}\frac23w^{3/2}\bigg|_{w=1}^{w=145}$
$=\dfrac\pi{54}(145^{3/2}-1)\approx101.522$

7 0

3 years ago

Giveing out 100 points to whoever gets it right! Need help soon!

RSB [31]

Answer:

225.5 sq. mm

Step-by-step explanation:

triangle:5x(9+4+4+4)=15x21÷2=157.5

5x(4+4)=5x8=40

7x4=28

157.5+40+28=157.5+68=225.5

5 0

1 year ago