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Sedaia [141]
3 years ago
5

Which type of transformation could cause a change in the period of a tangent or cotangent function? vertical shift phase shift v

ertical stretch horizontal stretch
Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

D. Horizontal stretch

Step-by-step explanation:

just did assignment

siniylev [52]3 years ago
7 0
The horizontal stretch is the correct answer. A period is the distance on the x-axis that it takes for the tangent or cotangent function to repeat itself. Stretching it out horizontally will lengthen that distance and therefore change the period.
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CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM​
Klio2033 [76]

Answer:

V ≈ 2011 cm³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = area of base × perpendicular height

V = πr²h ( r is the radius and h the height )

Here r = 8 and h = 10, thus

V = π × 8² × 10

  = π × 64 × 10 = 640π ≈ 2011 cm³ ( to nearest whole number )

3 0
2 years ago
Martin uses his power saw every 15 seconds.How many times did he use it in one hour ?​
Alina [70]

Answer:

  1. 60<em><u>÷</u></em><em><u>15</u></em><em><u> </u></em><em><u>=</u></em><em><u>4</u></em><em><u> </u></em>

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7 0
3 years ago
Read 2 more answers
Which points lie on the graph of f(x) = logor?
Mariana [72]

Answer:

9.1

Step-by-step explanation:

cus I seen it on usatesprep

8 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
If the simple interest on $3000 for 8 years is $1680, then what is the interest rate?
Fiesta28 [93]
R=i/pt
R=1680/3000*8=1,680÷24,000
=0.07*100=7%
3 0
3 years ago
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