Let's assume
length of rectangle =L
width of rectangle =W
You enclose 3 sides of the garden with 40 feet of fencing
so, we get
now, we can solve for L
we know that
area of rectangle is
now, we can plug
now, we can solve for W
we can use quadratic formula
we can take anyone value ..because both are giving positive value
first dimensions:
now, we can find L
so, length is 34.142feet
width is 2.929 feet
Second dimensions:
now, we can find L
so, length is 5.858feet
width is 17.071 feet
Answer:
n= 27
Step-by-step explanation:
To solve first subtract the 90-degree angle:
180-90= 90
Then, convert into an equation:
3n+9= 90
Subtract 9 from both sides:
3n=81
Then divide by 3:
n= 27
Hope this helps!
Answer:
I think the answer is D because it doesn't show that the bottom lengths are the same.
Step-by-step explanation:
Check the picture below.
since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16
![5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48\frac{6}{7}\impliedby \textit{perimeter}](https://tex.z-dn.net/?f=5x%20%2B%2016%5Cimplies%205%5Cleft%28%20%5Ccfrac%7B3%7D%7B7%7D%20%5Cright%29%2B16%5Cimplies%20%5Ccfrac%7B38%7D%7B7%7D%2B16%5Cimplies%20%5Ccfrac%7B38%2B112%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B150%7D%7B7%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bboth%20legs%7D%7D%7B%5Ccfrac%7B150%7D%7B7%7D%2B%5Ccfrac%7B150%7D%7B7%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bbase%7D%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B150%2B150%2B42%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B342%7D%7B7%7D%5Cimplies%2048%5Cfrac%7B6%7D%7B7%7D%5Cimpliedby%20%5Ctextit%7Bperimeter%7D)
Answer:
slope: -2/3 y intercept: (0,5)
Step-by-step explanation:
