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3 years ago

If Pietra walked 11 miles during the week, how many miles did the two girls walk together?

Mathematics

1 answer:

Mashutka [201]3 years ago

6 0

See what times 11 gives u ur answer

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Alannah, Colin and Hannah visit the park and collect conkers and acorns.

Alekssandra [29.7K]

Answer:

acorns

Step-by-step explanation:

20x=9y

9/20 to 5/9

5/9 of the acorns collected are from Hannah

9/20 of the conkers collected are from Hannah

5/9 is larger than 9/20

Hannah collected more acorns

8 0

2 years ago

What is the area of the following trapezoid?

KIM [24]

......................................3 yards?

8 0

4 years ago

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Simplify the cubed root of six over the fourth root of six

Ipatiy [6.2K]

Answer:

six raised to the one twelfth power

Step-by-step explanation:

The cubed root of 6/the fourth root of 6 equals (6^1/3)/(6^1/4)

6^((1/3)-(1/4))

6^((4-3)/12)

6^1/12

8 0

3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

4 years ago

The table shows the results of a class survey about pets. Suppose 53 students were surveyed. About how many students have one pe

kaheart [24]

I think the answer would be

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3 years ago