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3 years ago

Alexander has a square-shaped basket of apples. The

Mathematics

1 answer:

Sphinxa [80]3 years ago

4 0

Answer:

6 ft

Step-by-step explanation:

Side = √area = √36 = 6 ft (we have to find a positive number that multiply by itself gives 36

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While retreating, Fencer X parries Fencer Ys attack and ripostes, touching Y on the valid surface, which is registered on the ma

IgorLugansk [536]

Answer: Award a touch for X

Step-by-step explanation:

This is not a Mathematical question, it's a fencing question. It just requires the knowledge of the fencing sport.

Knowing the rules of the game, would let one know that fencer X landed the first legal touch on the valid surface of fencer Y.

Fencer Y's touch on Fencer X's valid surface arrives when fencer X already tripped while retreating and fell.

QED!

7 0

4 years ago

Simpliy the following expression log(x^3)-log(x^2)

notsponge [240]

Answer:

The answer is A

Step-by-step explanation:

4 0

4 years ago

Plz help I’ll give Brainliest

kvasek [131]

Answer:

1. y = -5/6x + 2

Write in slope-intercept form, y = mx + b

2. 46

3. x = 4

Isolate the variable by dividing each side by factors that don't contain the variable.

~Hoped this helped~

~Did it first! Brainiliest, please~

5 0

3 years ago

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use

QveST [7]

$\bf 27\implies 3^3\\\\
i^3\implies i\cdot i\cdot i\implies i^2\cdot i\implies -1\cdot i\implies -i\\\\
-----------------------------\\\\
x^3-27i=0\implies x^3+3^3(-i)=0\implies x^3+(3^3i^3)=0
\\\\\\
x^3+(3i)^3=0\\\\
-----------------------------\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3\\\\
-----------------------------\\\\$

$\bf (x+3i)[x^2-3ix+(3i)^2]=0\implies 
\begin{cases}
x+3i=0\implies \boxed{x=-3i}\\\\
x^2-3ix+(3i)^2=0
\end{cases}
\\\\\\
\textit{now, for the second one, we'd need the quadratic formula}
\\\\\\
x^2-3ix+(3i)^2=0\implies x^2-3ix+(3^2i^2)=0
$

$\bf x^2-3ix+(-9)=0\implies x^2-3ix-9=0
\\\\\\
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\implies x=\cfrac{3i\pm\sqrt{(-3i)^2-4(1)(-9)}}{2(1)}
\\\\\\
x=\cfrac{3i\pm\sqrt{(-3)^2i^2+36}}{2}\implies x=\cfrac{3i\pm\sqrt{-9+36}}{2}
\\\\\\
x=\cfrac{3i\pm\sqrt{27}}{2}\implies \boxed{x=\cfrac{3i\pm 3\sqrt{3}}{2}}$

7 0

3 years ago

This is the question

aivan3 [116]

Answer:

use desmos irs a graphing caculator it helped me gat all my answear with inequality

4 0

3 years ago