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aleksandrvk [35]
3 years ago
6

A supermarket has found that 60% of their customers spend more than $75 each visit. Whats the probability that the next 2 custom

ers will each spend more than $75? ×
Mathematics
1 answer:
spin [16.1K]3 years ago
7 0
Answer: 0.36 or 36%
60%=60/100=0.6

60% is the same as saying 60/100 or 0.6

To solve for the probability of this problem, we have to, multiply the odds of the two separate events together

event1 is a customer that spends more than 75$. The odds of that happening are .6

event 2 is a customer that spends more than 75$. The odds of that happening are .6

probability=event1*event2
probability=.6*.6 
probability=.36 or 36%
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Answer:

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Step-by-step explanation:

(159 + 833) * 6

= 992*6 = 5952

4 0
3 years ago
What are the points of trisection of the segment with endpoints (0,0) and (27,27) ?
stiks02 [169]

Given:

Endpoints of a segment are (0,0) and (27,27).

To find:

The points of trisection of the segment.

Solution:

Points of trisection means 2 points between the segment which divide the segment in 3 equal parts.

First point divide the segment in 1:2 and second point divide the segment in 2:1.

Section formula: If a point divides a line segment in m:n, then

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, the coordinates of first point are

Point\ 1=\left(\dfrac{1(27)+2(0)}{1+2},\dfrac{1(27)+2(0)}{1+2}\right)

Point\ 1=\left(\dfrac{27}{3},\dfrac{27}{3}\right)

Point\ 1=\left(9,9\right)

Using section formula, the coordinates of first point are

Point\ 2=\left(\dfrac{2(27)+1(0)}{2+1},\dfrac{2(27)+1(0)}{2+1}\right)

Point\ 2=\left(\dfrac{54}{3},\dfrac{54}{3}\right)

Point\ 2=\left(18,18\right)

Therefore, the points of trisection of the segment are (9,9) and (18,18).

6 0
3 years ago
Plz help me if you're nice. If wrong answer i'll report you
Anna [14]

Answer

z= 14

Step-by-step explanation:

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3z=60-18

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z= 14

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