Answer is false
Here sample size = 100
Sample propotion = 38%
i.e. p =0.38 and q = 1-p =0.62
p follows a normal with mean = 0.38 and std error =
For 95% z value = 1.96
Hence margin of error = 1.96 (std error) = 0.0951
Confidence interval = (0.38-0.0951, 0.38+0.0951)
=(0.2949, 0.4751)
= (29.49%, 47.51%)
Hence given confidence interval is from 33% to 43% (to the nearest percent).
False