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Brut [27]
4 years ago
6

A(n)= -5+ (n=1)(4) I need help with this answer please

Mathematics
2 answers:
Andreyy894 years ago
7 0

Answer:

A=-1

Step-by-step explanation:

A(n)=-5+(1)(4)

A(n)=-5+4

A(n)=-1

A(1)=-1

A=-1

postnew [5]4 years ago
3 0

Answer:

A_n=A_{n-1}+4 \\ A_1= - 5

Step-by-step explanation:

Assuming you want to write a recursive formula, for

A_n =  - 5 + (n - 1)(4)

We recall that d=4, is the common difference in this explicit definition.

The recursive formula is given by:

A_n=A_{n-1}+d

We substitute to get:

A_n=A_{n-1}+4

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<img src="https://tex.z-dn.net/?f=8%28%20%7B4%7D%5E%7B2%7D%29%20%2B%20%20%7B2%7D%5E%7B4%7D%20" id="TexFormula1" title="8( {4}^{2
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<em><u>Solution:</u></em>

Given expression is:

8(4)^2+2^4

We have to evaluate the above given expression

We know that,

(4)^2 = 4 \times 4 = 16

2^4 = 2 \times 2 \times 2 \times 2=16

Substituting these in above given expression, we get

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Thus the given expression 8(4)^2+2^4 is equal to 144 or 12^2

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