The original plot of land had dimensions (200 m)(300 m) = 60000 m^2, which is the product of L and W.
Twice that area would be 2(60000 m^2) = 120000 m^2 = (L+x)(W+x). Expanding this, we get LW + Lx + Wx + x^2 = 120000 m^2. Treat L and W as constants and x as the variable:
x^2 + (L+W)x + LW -120000 = 0 and LW=60000 (from above).
Substituting,
x^2 + (L+W)x + 60000 - 120000 = 0, or x^2 + (L+W)x - 600000 = 0. Unfortunately, we don't know the value of L+W (unless we assume that L = 300 m and W = 200 m). We could use the quadratic formula to solve the above equation for x in terms of (L+W).
I note that you wrote, "If the original plot had an area of 200 by 300 m^2 .... "
This is inappropriate and should read "If the original plot of land had DIMENSIONS 200 m by 300 m ...
Ensure that you have copied down the original problem exactly as it was presented to you.
Answer:
28
Step-by-step explanation:
4x7=28
14x2=28
Answer:
x= 5a -3/9
Step-by-step explanation:
-5a+9x=-27
9x=5a-27
x= 5a-27÷9
x= 5a - 27×1/9
x= 5a -3/9
Hope this helps
Keep Smiling :)
Answer:
I am not certain but I think division
Answer:
Its option c
Step-by-step explanation:
The equation is written in point-slope form:-
y - y1 = m(x - x1) where m = slope and (x1, y1) is a point on the line.
So comparing this with the equation in the question:-
The point is (1, 9) and the slope is 3/2
