Answer:
A) sample mean = $1.36 million
B) standard deviation = $0.9189 million
C) confidence interval = ($1.93 million , $0.79 million)
*since the sample size is very small, the confidence interval is not valid.
Step-by-step explanation:
samples:
- $2.7 million
- $2.4 million
- $2.2 million
- $2 million
- $1.5 million
- $1.5 million
- $0.5 million
- $0.5 million
- $0.2 million
- $0.1 million
sample mean = $1.36 million
the standard deviation:
- $2.7 million - $1.36 million = 1.34² = 1.7956
- $2.4 million - $1.36 million = 1.04² = 1.0816
- $2.2 million - $1.36 million = 0.84² = 0.7056
- $2 million - $1.36 million = 0.64² = 0.4096
- $1.5 million - $1.36 million = 0.14² = 0.0196
- $1.5 million - $1.36 million = 0.14² = 0.0196
- $0.5 million - $1.36 million = -0.86² = 0.7396
- $0.5 million - $1.36 million = -0.86² = 0.7396
- $0.2 million - $1.36 million = -1.16² = 1.3456
- $0.1 million - $1.36 million = -1.26² = 1.5876
- total $8.444 million / 10 = $0.8444 million
standard deviation = √0.8444 = 0.9189
95% confidence interval = mean +/- 1.96 standard deviations/√n:
$1.36 million + [(1.96 x $0.9189 million)/√10] = $1.36 million + $0.57 million = $1.93 million
$1.36 million - $0.57 million = $0.79 million
Answer:
113.1 yards
Step-by-step explanation:
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<h2>
Answer:</h2>
Hope it work for u
<h2>
Step-by-step explanation:</h2>
We can make points from the given figure as ,
1 point =(x1, y1)=(-2, -3)
2nd point =(x2, y2)= (0, -6)
3rd point = (x3, y3)=(2 , -9)
Now the equation of line is,
<h2>
Y=m X+ c where m is slope and c is constant </h2>
now two point formula of slope is ,
<h2>
m = y2-y1/x2-x1</h2>
putting points in it we get
m=(-6-(-3))/(0-(-2)
m=-3/2 is slope
Now to find C putt the value of m and 3rd point in equation of line we get
y3=m(x3)+c
-9=(-3/2)(2) +c
C= -9+3
C=-6 is value of c
Now at last putt the value of C and m in equation of line we get the required equation ,
<h2><u>
Y=(-3/2)X-6 </u>
Ans</h2>
