1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula:
![d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D%20)
where
![(x_{1},y_{1})](https://tex.z-dn.net/?f=%28x_%7B1%7D%2Cy_%7B1%7D%29)
are the coordinates of the first point
![(x_{2},y_{2})](https://tex.z-dn.net/?f=%28x_%7B2%7D%2Cy_%7B2%7D%29)
are the coordinates of the second point
Length of WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
![d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}](https://tex.z-dn.net/?f=d_%7BWZ%7D%3D%20%5Csqrt%7B%284-1%29%5E2%2B%282-0%29%5E2%7D%20)
![d_{WZ}= \sqrt{(3)^2+(2)^2}](https://tex.z-dn.net/?f=d_%7BWZ%7D%3D%20%5Csqrt%7B%283%29%5E2%2B%282%29%5E2%7D)
![d_{WZ}= \sqrt{9+4}](https://tex.z-dn.net/?f=d_%7BWZ%7D%3D%20%5Csqrt%7B9%2B4%7D)
![d_{WZ}= \sqrt{13}](https://tex.z-dn.net/?f=d_%7BWZ%7D%3D%20%5Csqrt%7B13%7D)
We know that all the sides of a rhombus have the same length, so
![d_{YZ}= \sqrt{13}](https://tex.z-dn.net/?f=d_%7BYZ%7D%3D%20%20%5Csqrt%7B13%7D%20)
![d_{XY}= \sqrt{13}](https://tex.z-dn.net/?f=d_%7BXY%7D%3D%20%5Csqrt%7B13%7D%20)
![d_{XW}= \sqrt{13}](https://tex.z-dn.net/?f=d_%7BXW%7D%3D%20%5Csqrt%7B13%7D%20)
Now, we just need to add the four sides to get the perimeter of our rhombus:
![perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}](https://tex.z-dn.net/?f=perimeter%3D%20%5Csqrt%7B13%7D%20%2B%20%5Csqrt%7B13%7D%20%2B%20%5Csqrt%7B13%7D%20%2B%20%5Csqrt%7B13%7D%20)
We can conclude that the perimeter of our rhombus is
square units.
2. To solve this, we are going to use the arc length formula:
![s=r \alpha](https://tex.z-dn.net/?f=s%3Dr%20%5Calpha%20)
where
![s](https://tex.z-dn.net/?f=s)
is the length of the arc.
![r](https://tex.z-dn.net/?f=r)
is the radius of the circle.
![\alpha](https://tex.z-dn.net/?f=%20%5Calpha%20)
is the central angle in radians
We know form our problem that the length of arc PQ is
![\frac{8}{3} \pi](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B3%7D%20%20%5Cpi%20)
inches, so
![s=\frac{8}{3} \pi](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B8%7D%7B3%7D%20%5Cpi)
, and we can infer from our picture that
![r=15](https://tex.z-dn.net/?f=r%3D15)
. Lest replace the values in our formula to find the central angle POQ:
![s=r \alpha](https://tex.z-dn.net/?f=s%3Dr%20%5Calpha%20)
![\frac{8}{3} \pi=15 \alpha](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D%20%5Cpi%3D15%20%5Calpha%20)
![\alpha = \frac{\frac{8}{3} \pi}{15}](https://tex.z-dn.net/?f=%20%5Calpha%20%3D%20%20%5Cfrac%7B%5Cfrac%7B8%7D%7B3%7D%20%5Cpi%7D%7B15%7D%20)
Since ![\alpha =POQ](https://tex.z-dn.net/?f=%20%5Calpha%20%3DPOQ)
,
We can conclude that the measure of the central angle POQ is
3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section.
We can conclude that the draw of our cross section is: