Answer:
The roots of the equation 2m²+3=m are non-real roots.
Step-by-step explanation:
Given equation:
2m²+3=m
2m²-m+3=0
Here, from the equation we can obtain the following values:
a = 2, b = -1, c = 3
Discriminant of an equation is given as:
D = b²-4ac
= (-1)²-4(2)(3)
= 1 - 21
= -20
Discriminant can tell what kinds of roots the equation have.
In our case, the discriminant is less than 0.
When D < 0, the roots of the equation are complex conjugates.(non-real)
Used show you have more than what is needed. Example is you need 6 slices of pizza for all your friends but have 7 slices you have more than is needed.
Remember, you can do anything to an equation as long as you do it to both sides
for inequalities, if you multiply or divide both sides by a negative number, you flip the direction of the inequality sign
-5.3≥6.7+4.3+q
add like terms
-5.3≥11+q
minus 11 both sides
-16.3≥q
q≤-16.3
das is da soltuion
The value of dividing x^2-3x+9 by x-2 is x + 3
<h3>Ways of dividing polynomials</h3>
There are several ways to divide polynomial functions; some of these ways include
- By factorization
- By long division
- By synthetic division
- By using technology such as graph
<h3>How to divide the polynomials?</h3>
The expression for the polynomial division is given as:
x^2-3x+9/x-2
To divide polynomial functions, we make use of the division by factorization method
Start by expanding the numerator of the polynomial division
x^2-3x+9/x-2 = x^2 + 3x - 6x + 9/x-2
Factorize the equation
x^2-3x+9/x-2 = x(x + 3) - 2(x + 3)/x - 2
Factor out x + 3 from the numerator
x^2-3x+9/x-2 = (x- 2)(x + 3)/x - 2
Cancel out the common factors
x^2-3x+9/x-2 = x + 3
Hence, the value of dividing x^2-3x+9 by x-2 is x + 3
Read more about polynomial division at:
brainly.com/question/25289437
#SPJ1
0.
The x on the bottom will cancel out the x on the top here.
