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levacccp [35]
3 years ago
6

Help with this plz!!

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0
\frac{22}{7} n \ \textgreater \ \frac{4}{3}


\frac{22}{7} ( \frac{2}{5}) \ \textgreater \ \frac{4}{3}
. --- False


\frac{22}{7} ( \frac{2}{9}) \ \textgreater \ \frac{4}{3}
 --- False


\frac{22}{7} (1) \ \textgreater \ \frac{4}{3}
 --- True


\frac{22}{7} ( \frac{1}{3}) \ \textgreater \ \frac{4}{3}
--- False

\frac{22}{7} ( \frac{3}{2}) \ \textgreater \ \frac{4}{3}
--- True
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There are 3 cups each cup is full with 5/8 of water how much water is their in all
evablogger [386]

1 cup = 8 ounces

so you'll have 5 ounces in each cup

5/8+5/8+5/8=15/8 (roughly 15 ounces or just under 2 cups of water)

4 0
4 years ago
Dilate the rectangle below by a scale factor of 2. If the current side lengths are 15
Anna71 [15]

Answer:

AB and CD would be 30

AC and BD would be 16

Step-by-step explanation:

The scale factor is what you multiply the sides by. Dilate means wider or larger so you multiply each side by the scale factor of 2 to get the higher scaled rectangle.

4 0
3 years ago
Solve for x: 3|2x + 41 - 2 = 22
krek1111 [17]

Answer:

Your answer is x= −17/32

7 0
3 years ago
Mark and Heather Starr are celebrating their 25th anniversary by having a reception at a local reception hall. They have budgete
valkas [14]

Answer:

<h2> 62 persons</h2>

Step-by-step explanation:

Step one:

given data

total budget=$2500

we are told that the hall charges $60 for cleanup, the amount is a fix charge

and per person is $39

let the number of persons be x

The model for the situation is described by y=mx+c

Step two:

2500=39x+60

solve for x

2500-60=39x

2440=39x

divide both sides by 39 we have

x=2440/39

x=62.56

The greatest number of people that they may invite and still stay within their budget.  is 62

4 0
3 years ago
In the diagram below, AC and CB, AB and CD, and m(angle)A=33 degrees. Find M(angle)B
hoa [83]

Answer:

15°.

Step-by-step explanation:

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Have a good Day!

7 0
3 years ago
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