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3 years ago

What does he mean on question one

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

You plug -2 in for the function k(p) and add it to the function g(w), getting
(-2+3)*(-2-7)+(-2-5)^2=1*-9+49=40 for a - I challenge you to do B on your own!

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SHOW YOUR WORK! ??????????

Verizon [17]

Answer:

<h2>Solved in the attachment!! </h2>

Step-by-step explanation:

<h2>HOPE IT HELPS YOU!!</h2>

7 0

2 years ago

Can some one help me. btw the answer is not C.

Anit [1.1K]

Answer:

Step-by-step explanation:

Given

x² + 6x

To complete the square

add ( half the coefficient of the x- term )² to x² + 6x

x² + 6x + (3)²

= x² + 6x + 9

= (x + 3)²

3 0

3 years ago

7) -6x + 6y=6<br> -6x + 3y=-12

Gre4nikov [31]

Answer:

(5,6)

Step-by-step explanation:

-6x+6y=6

-6x + 3y =-12

Multiply the first equation by -1

6x-6y=-6

Add this to the second equation

6x-6y=-6

-6x + 3y =-12

---------------------

-3y = -18

Divide each side by -3

-3y/-3 = -18/-3

y =6

Now we need to find x

6x - 6y = -6

6x -6(6) = -6

6x -36 = -6

Add 36 to each side

6x-36+36 = -6+36

6x = 30

Divide each side by 6

6x/6 = 30/6

x =5

3 0

4 years ago

Janine has two important tests to study for. If she plans to divide her study time equally between both tests, how long should s

docker41 [41]

90/2 = 45
45 minutes each.

3 0

3 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago