Answer: 20
Step-by-step explanation:
 
        
                    
             
        
        
        
A=600⋅(1.0001)^365t
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Answer:
<em>Your Interquartile range (IQR) would be 19.</em>
Step-by-step explanation:
-5, 1, 3, 7, 8, 10, 32, 36
Median: 7.5
Lower quartile: 2
Upper quartile: 21
Interquartile range: 21 - 2 = 19
 
        
             
        
        
        
Answer:
<u>Perimeter</u>: 
= 58 m (approximate)
= 58.2066 or 58.21 m (exact)
<u>Area:</u>
= 208 m² (approximate)
= 210.0006 or 210 m² (exact)
Step-by-step explanation:
Given the following dimensions of a rectangle: 
length (L) =  meters
 meters
width (W) =  meters
 meters
The formula for solving the perimeter of a rectangle is:
P  = 2(L + W) or 2L + 2W
The formula for solving the area of a rectangle is: 
A = L × W
<h2>Approximate Forms:</h2>
In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  
13² = 169
14² = 196
15² = 225
16² = 256
Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle. 
P  = 2(L + W) 
P = 2(13 + 16) 
P = 58 m (approximate)
A = L × W
A = 13 × 16
A = 208 m² (approximate)
<h2>Exact Forms:</h2>
L =  meters = 15.8745 meters
 meters = 15.8745 meters
W =  meters = 13.2288 meters
 meters = 13.2288 meters
P  = 2(L + W) 
P = 2(15.8745 + 13.2288)
P = 2(29.1033)
P = 58.2066 or 58.21 m
A = L × W
A = 15.8745 × 13.2288
A = 210.0006 or 210 m² 
 
        
             
        
        
        
Answer:
Step-by-step explanation:
-39