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3 years ago

What is the slope and y-intercept of the graph? (2.1) (-1.4)

2 answers:

5 0

-1 and the y-intercept is 6 I think, I used another app called math w.a.y (remove the periods I can’t put the actual app name)

Serggg [28]3 years ago

4 0

Answer:

The slope is -1

Step-by-step explanation:

Use the formula m=y2-y1/x2-x1

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The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

3 years ago

The sum of three times a number d and 5 is 17?

andre [41]

Answer:

3 times 4 + 5 = 17

Step-by-step explanation:

3d+5=17

-5 -5

________

3d = 12

__ __

3 3

d = 4

7 0

3 years ago

Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He then created both a histo

Scilla [17]

Answer:

(a) The correct option is (A).

(b) The correct option is (B).

Step-by-step explanation:

Nam collected the data for the distance traveled by all the cars in his car lot.

(a)

A histogram is a bar graph representing the distribution of a random variable. The height of the bars of the histogram represents the frequency for a specific interval.

If Nam wants to know how many vehicles had driven more than 200,000 km, the histogram would be the best display of this data. This is because the histogram shows the frequency for various interval values.

The correct option is (A).

(b)

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart)
First Quartile (shown by the bottom line of the box)
Median (or the second quartile) (shown as a line in the center of the box)
Third Quartile (shown by the top line of the box)
Maximum (shown at the top of the chart).

So, if Nam wants to find whether the median distance was approximately 140,000 km, a box plot would be a better choice. This is because the box plot represents the median of the data by a line within the box.

The correct option is (B).

4 0

3 years ago

Read 2 more answers

Pls give two answers for good measure

katrin2010 [14]

Step-by-step explanation: To solve for x in this inequality,

your goal is the same as it would be if you were solving an

equation, to get x by itself on one side.

Since 5 is being subtracted from x, add 5 to both sides of the inequality.

On the left, the -5and +5 cancel out and on the right, -2 + 5 is 3.

So we have x ≥ 3.

When graphing, start with a closed dot at +3 because x is

not just greater than +3, it's equal to it as well.

Then draw an arrow to the right, like I have done below.

8 0

3 years ago

Read 2 more answers

Does the following equation determine y to be a function of x? y square=x+3

Phantasy [73]

Answer:

∴ y² = x + 3 is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

- The definition of the function is every input (x) has only one

output (y)

- Ex:

# y = x + 1 where x ∈ R , is a function because every x has only

one value of y

# y² = x where x ∈ R , is not a function because y = ±√x, then one

x has two values of y

* Lets solve the problem

∵ y² = x + 3

- Find y by taking √ for both sides

∴ y = ± √(x + 3)

- That means y = √(x + 3) and y = - √(x + 3)

∵ (x + 3) must be greater than or equal zero because there is no

square root for negative number

∴ x + 3 ≥ 0 ⇒ subtract 3 from both sides

∴ x ≥ -3

∴ x must be any number greater than or equal -3

- Let x = 0

∴ y = √(0 + 3) = √3 and y = - √(0 + 3) = -√3

∴ x = 0 has two values of y ⇒ y = √3 and y = -√3

- Any value of x greater than or equal 3 will have two values of y

∴ y² = x + 3 is not a function

5 0

3 years ago