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zhuklara [117]
3 years ago
7

What integer most nearly approximates (50)(80) ? A.20 B.40 C.63 D.200 E. 2.000

Mathematics
2 answers:
LiRa [457]3 years ago
7 0
And I opp sk sk hsjsjzjzjaksksksjsjshsgsiajj . Ksjsbsjsizuzvsbsizgzbsj!
BARSIC [14]3 years ago
3 0
The answer is e I took the test
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Suppose that Frida selects a ball by first picking one of two boxes at random and then selecting a ball from this box at random.
BaLLatris [955]

Answer:

3/4

Step-by-step explanation:

Given the following :

Number of boxes = 2

First box :

White balls = 3

Blue balls = 2

Second box:

White balls = 4

Blue balls = 1

What is the probability that Frida picked a ball from the first box if she has selected a blue ball?

Probability (P) = (required outcome / Total possible outcomes)

Probability of picking first box : P(F) = 1/2

Probability of not picking second box :P(S) 1/2

Probability of picking blue from first box : P(B | F) = 3/5

Probability of picking blue, but not from first box : P(Blue not from second box) P(B|S) = 1/5

probability that Frida picked a ball from the first box if she has selected a blue ball?

P(F) * P(B|F) ÷ (P(F) * P(B|F)) + (P(S) * P(B|S))

(1/2 * 3/5) ÷ ((1/2 *3/5) + (1/2 * 1/5)

3/10 ÷ (3/10 + 1/10)

3/10 ÷ 4/10

3/10 * 10/4

= 3/4

7 0
3 years ago
Given the following figures HOUSE and H'O'U'S'E', describe a transformation that maps the pre-image onto its image. Use complete
babymother [125]

Answer:

hahhbabbwbbbshhshhauyydb e hsuhshbdhwyysgdvbsbhhshd

4 0
3 years ago
Read 2 more answers
Which table contains the vertex of the graph represented by y=x^2-6x+4?
notka56 [123]

Answer:

Table B

Vertex is (3,-5)

Step-by-step explanation:

We are given with an equation of a parabola y=x^2-6x+4

Let is convert it into standard form of a parabola

y=x^2-6x+4

adding and subtracting 9 in the right hand side of the =

y=x^2-6x+9-9+4

y=x^2-2\times 3\times x+ 3^2-9+4

the first three terms of the right hand side forms the expression of square of difference

a^2-2 \times a \times b+b^2 = (a-b)^2

Hence

y=(x-3)^2-5

adding 5 on both sides we get

(y+5)=(x-3)^2

Comparing it with the standard equation of a parabola

X^2=4\times \frac{1}{4} \times Y

where X=x-3 and Y=y+5

The vertex of X^2=4\times \frac{1}{4} \times Y will be (0,0)

and thus vertex of

(y+5)=(x-3)^2 will be (3,-5)

Hence the Table B is our right answer

5 0
3 years ago
Please help what is the answer to this<br> Logx + 2Log5
melomori [17]

Answer:

log 0 is undefined. It's not a real number, because you can never get zero by raising anything to the power of anything else

Step-by-step explanation:

I'm sorry it did not help

5 0
3 years ago
The midpoint of JK is M(5, 6). One endpoint is J(7, 7). Find the coordinates of the other
iris [78.8K]

Answer:

K(3, 5)

Step-by-step explanation:

let K(x, y)

then x + 7 = 5*2 and y + 7 = 6*2 by the midpoint theorem.

solving, x = 3, y = 5

6 0
3 years ago
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