5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
We have on the top of the figure one semircle, on the bottom of the figure another semicircle, to the left of the figure a line segment, and to the right of the figure another line segment, then we have a total of two semicircles and two line segments.
Answer: Fourth option: two semicircles and two line segments
Solution: The sum of probabilities of all the sample points must equal 1. And the probability of getting a head is equal to the probability of getting a tail. Therefore, the probability of each sample point (heads or tails) must be equal to 1/2. Let's repeat the experiment of Example 1, with a die instead of a coin.
Answer:(B)
Step-by-step explanation:
it is because for the people your final price was 200 you don't know how much money the people donated
