Answer: Mr Smith bought 7 pepperoni pizza
Step-by-step explanation:
Step 1
cost of cheese pizza =$11
pepperoni pizza cost =$12.50
let number cheese pizza be represented as c
and number of pepperoni pizza be represented as p
such that the total number of pizza bought which equals 13 can be represented as
c+ p= 13
and total cost of both pizza can be expressed as
11c+ 12.50p =153.50
Step 2 Solving
c+ p= 13
11c+ 12.50p =153.50
By elimination method, Multiply equation 1 by 11 and subtract the new equation from equation 2
11c+ 12.50p =153.50
11c+ 11p=143.
1.5p =10.5
p= 10.5/ 1.5 =7
c+ p= 13
c= 13-p =13-7=6
Therefore Mr Smith bought 6 cheese pizza and 7 pepperoni pizza
Answer:
0.448 seconds
Step-by-step explanation:
d = -16t² -4t + 412
find t when d = 407
substituting d = 407 into the equation:
407 = -16t² -4t + 412 (subtract 407 from both sides)
-16t² -4t + 412 - 407 = 0
-16t² -4t + 5 = 0 (multiply both sides by -1)
16t² + 4t - 5 = 0
solving using your method of choice (i.e completing the square or using the quadratic equation), you will end up with
t = (-1/8) (1 + √21)= -0.70 seconds (not possible because time cannot be negative)
or
t = (-1/8) (1 -√21) = 0.448 seconds (answer)
1 pt = 0.5 qts.....so 720 pts = (720 * 0.5) = 360 qts
1 hr = 60 minutes
360/60 = 6
720 pt/hr = 6 qts/min
The stem and leaf plot will look like:
6 | 1 5 8 - 3 scores
7 | 1 7 7 9 - 4 scores
8 | 2 3 4 5 7 9 - 6 scores
9 | 0 1 4 7 9 - 1 score
To total up the number of students who scored less than 90, we have 3 under 60-69, 4 under 70-79, and 6 under 80-89, so this is 3 + 4 + 6. This is the third choice.
