Let's say x = full price tickets
Let's say y = student tickets
We can write two equations:
From "585 tickets were sold" we can make the equation:
x + y = 585
And from "Full-price ticket is $2.50 and student ticket is $1.75 and total receipts is $1,217.25"...we can make the equation:
2.50x + 1.75y = 1,217.25
So now we can use substitution to find our answer...since we only have to find how many student tickets...we will solve the first equation for x so we can plug that into the 2nd equation to solve for y.
x + y = 585
x + y - y = 585 - y
x = 585 - y
Now we plug that into our 2nd equation: 2.50 (585 - y) + 1.75y = 1217.25
Distribute your 2.50
1462.5 - 2.50y + 1.75y = 1217.25
Add the y's: 1462.5 - 0.75y = 1217.25
Subtract 1462.5 from both sides:
1462.5 - 0.75y - 1462.5= 1217.25 - 1462.5
-0.75y = -245.25
Divide both sides by -0.75:
y = -245.25/-0.75
y = 327
There were 327 student tickets :)
Answer:
it's the last one i mean 4&1/4
Answer:
D)
Step-by-step explanation:
4 is an evident zero of the equation x^3 - 64.
x^3 - 64 can only be factorized with (x-4) and not with (x+4)
because x - 4 = 0 <==> x = 4 and 4^3 -64 = 0
Developing B) would be:
x^3 + 4x^3 + 16x - 4x^2 - 16x - 64 = 5x^3 - 4x^2 -64
So it doesn't match so it's D)
<u>Question 11</u>
1)
,
(given)
2)
(reflexive property)
3)
(ASA)
4)
(CPCTC)
<u>Question 12</u>
1) Isosceles
with
,
(given)
2)
(angles opposite congruent sides in a triangle are congruent)
3)
and
are supplementary.
and
are supplementary (angles that form a linear pair are supplementary)
4)
(supplements of congruent angles are congruent)
5)
(SAS)
6)
(CPCTC)
7)
is an isosceles triangle (a triangle with two congruent sides is isosceles)
<em>Note: I changed the names of the segments in Question 11 because of the word filter.</em>
Answer: i am almost positive its (A)
i really hope im not wrong because this answer is the only one that has a stable rising action going up by the same number it did with the number before it. if its not right then your other option is (D)
Step-by-step explanation: