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Nata [24]
2 years ago
12

A line that passes through the point (4, 2) and has the slope of -3/2

Mathematics
1 answer:
mash [69]2 years ago
8 0
The answer is: y = -3/2 x + 8

Graph:

To find the answer we use the formula;

y-y1 = M1 (x - x1)

y-2 = -3/2 (x-4)

When fully solved: the answer is:
y = -3/2 x + 8

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Please help due tomarrow good luck
amid [387]

Answer:

125+1024x

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5 0
3 years ago
Read 2 more answers
Use the diagram to complete the statement.
Dima020 [189]

Answer:

∠FJH ≅ ∠BJA

Step-by-step explanation:

From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite

So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA

4 0
3 years ago
Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.
jeka94

Answer:

x=4+2\sqrt{3}

x=4-2\sqrt{3}

Step-by-step explanation:

<u>Completing the square</u>

when  ax^2+bx+c=0

Given equation:

3x^2-24x+40=28

Subtract 40 from both sides:

\implies 3x^2-24x=-12

Divide both sides by 3:

\implies x^2-8x=-4

Add the square of half the coefficient of x to both sides:

(\frac{b}{2})^2=(\frac{-8}{2})^2=16

\implies x^2-8x+16=-4+16

Factor the left side and simplify the right side:

\implies (x-4)^2=12

Square root both sides:

\implies x-4=\pm\sqrt{12}

Add 4 to both sides and simplify the radical:

\implies x=4\pm\sqrt{4 \cdot 3}

\implies x=4\pm\sqrt{4}\sqrt{3}

\implies x=4\pm2\sqrt{3}

5 0
1 year ago
Please help! double points. thanks
Gala2k [10]

Check the picture below.

so, hmmm notice, since i² = -1 and i⁴ = 1, whenever the exponent is only divisible by 2, the value will be -1, and whenever the exponent is divisible by 4, we end up with a +1, so every subsequent even exponent is simply cancelling the previous value, if we take that to the even value of 100, which has 50 pairs of those, we end up with, yeap, you guessed it, 0.

4 0
2 years ago
Given m 1= 65, find the measure of each missing angle.Givd your reasoning
lorasvet [3.4K]

Answer:

Step-by-step explanation:

Given:

m∠1 = 65°

Since. ∠1 and ∠2 are the angles of linear pair,

m∠1 + m∠2 = 180°

65° + m∠2 = 180°

m∠2 = 115°

m∠1 = m∠3 [Vertical angles]

m∠3 = 115°

Since, ∠1 and ∠4 is the linear pair of angles,

m∠1 + m∠4 = 180°

65° + m∠4 = 180°

m∠4 = 180 - 65 = 115°

m∠4 + m∠5 = 180° [Consecutive interior angles between the parallel lines]

115° + m∠5 = 180°

m∠5 = 180° - 115° = 65°

m∠5 + m∠6 = 180° [Linear pair of angles]

65° + m∠6 = 180°

m∠6 = 115°

m∠5 = m∠7 [Vertical angles]

m∠5 = m∠7 = 65°

m∠6 = m∠8 [Vertical angles]

m∠6 = m∠8 = 115°

6 0
2 years ago
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