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3 years ago

A=1/2bh solve for b

1 answer:

6 0

$A=\dfrac{1}{2}bh\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\2A=bh\ \ \ \ \ |divide\ both\ sides\ by\ h\\\\\boxed{b=\dfrac{2A}{h}}$

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3√3 AS A WHOLE RADICAL

Andrews [41]

Answer:

√27

Step-by-step explanation:

3 × √3

The square of 3 is 9.

√9 × √3

√(9 × 3)

Multiply.

√27

3√3 as a whole radical is √27.

6 0

3 years ago

The picture below shows a pole and its shadow:

scZoUnD [109]

Answer:

Step-by-step explanation:

You need to use Pythagorean's Theorem to find the height of the pole. Namely,

$pole^2+15^2=113^2$ and

$pole^2=113^2-15^2$ and

$pole^2=12769-225$ and

$pole^2=12544$ so

pole = 112 cm

8 0

4 years ago

Cuánto es 729 entre 38

riadik2000 [5.3K]

Answer: 19.1842

Step-by-step explanation:

8 0

3 years ago

Solve the linear differential equation 2xy' + y = 2√x

77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

$\frac{dy}{dx}+P(x)y=Q(x)$

For this case, we can rewrite the equation as:

$\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}$

Here $P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}$

To find the solution (y(x)), we can use the integration factor method:

$Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx$

Then $F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}$

So, we can find:

$y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C$

Suppose that $x\in \double R$ , then $\sqrt{|x|}=\sqrt{x}$ , and we find:

$y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}$

To check our solution is right or not, put your y(x) back to the ODE:

$y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}$

$2xy'=\frac{x-C}{\sqrt{x}}$

$2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}$

(it means your solution is right)

3 0

2 years ago

The coordinates of the vertices of trapezoid ABCD are A (2,6), B (5,6), C (7,1), and D (-1,1). The coordinates of the vertices o

likoan [24]

Answer:

Correct answer is option C.

Step-by-step explanation:

Trapezoid ABCD ≅ trapezoid A'B'C'D'

You can reflect trapezoid ABCD across the x-axis and then rotating it 90°clockwise.

4 0

3 years ago

Read 2 more answers