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iragen [17]
4 years ago
15

I did some work but I still can't seem to find X.

Mathematics
1 answer:
Luda [366]4 years ago
7 0

since ΔQRS similar to ΔQRP, then

SR/QR = QR/PR

x/12 = 12/(3.5+x)

x(3.5+x) = 12²

x² + 3.5x = 144

x² + 3.5x - 144 = 0

x =  \frac{ - 3.5 +  \sqrt{ {3.5}^{2}   + 4 \times 144} }{2}  \\  =  \frac{ -  \frac{7}{2} +  \sqrt{ \frac{49}{4}  + 576}  }{2}  \\  =  \frac{ - 7 +  \sqrt{49 + 2304} }{4}  \\  =  \frac{ - 7 +  \sqrt{2353} }{4}

approximately 10.38

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Find the area of the convex polygon with vertices (0,5), (-1,2), (4,4), (-3,-4) and (2,0).
Afina-wow [57]

The area of the convex polygon is 43/2 square units

<h3>How to determine the area of the convex polygon?</h3>

The vertices are given as:

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The area is then calculated as:

A = \frac 12(\left[\begin{array}{cc}x_1&x_2\\y_1&y_2\end{array}\right] + \left[\begin{array}{cc}x_2&x_3\\y_2&y_3\end{array}\right] + ....+\left[\begin{array}{cc}x_n&x\\y_n&y\end{array}\right] )

So, we have:

A = \frac12 * (|-1 * 5 - 2 * 0 + 0 * 4 - 5 * 4 + 4 * 0 - 4 * 2 + 2 * -4 - 0 * -3 -3 * 2 + 4 * 1|)

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A = \frac12 * (|-43|)

Remove the absolute bracket

A = \frac12 * 43

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Hence, the area of the convex polygon is 43/2 square units

Read more about convex polygon at:

brainly.com/question/14522707

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