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Svetach [21]
3 years ago
14

Which of them isn’t equal??

Mathematics
1 answer:
Artemon [7]3 years ago
8 0

a)\ \sin x\cos x\\\\b)\ \dfrac{1}{2}\sin(2x)=\dfrac{1}{2}\cdot2\sin x\cos x=\sin x\cos x\\\\c)\ \sin^2x\cot^2x=\sin^2x\cdot\dfrac{\cos^2x}{\sin^2x}=\cos^2x\\\\d)\ \tan x\cos^2x=\dfrac{\sin x}{\cos x}\cdot\cos^2x=\sin x\cos x\\\\Answer:\ c).

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Factorise fully <br>-14x - 8<br><br>ease do quick, will mark brainiest!​
OleMash [197]

Answer:

-2( 7x+4)

Step-by-step explanation:

-14x - 8

Factor out -2

-2*7x -2*4

-2( 7x+4)

5 0
4 years ago
Read 2 more answers
Which sequence represents an arithmetic sequence?
MArishka [77]

Answer:

D

Step-by-step explanation:

We know that an arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is always constant.

−5, −7, −10, −14, −19, …

Here difference between -5 and -7 is -2

But difference between -10 and -7 is -3

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

1.5, −1.5, 1.5, −1.5, …  

Here difference between 1.5 and -1.5 is 3

But difference between -1.5 and 1.5 is 3

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

4.1, 5.1, 6.2, 7.2, …  

Here difference between 4.1 and 5.1 is 1

But difference between 6.2 and 5.1 is 1.1

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

−1.5, −1, −0.5, 0, …

Here difference between -1.5 and -1 is 0.5

But difference between -1 and -0.5 is 0.5

⇒ Difference is constant.

Therefore, this sequence represents an arithmetic sequence.

plz mark brainliest

7 0
3 years ago
Give an indirect proof of the following statement
arlik [135]
Complicated answer.............
3 0
4 years ago
Write a proof for the conjecture using the contrapositive. <br> If 5x + 7 = -13, then x = -4.
KonstantinChe [14]

Answer:

ans x=4

Step-by-step explanation:

  • 5x + 7 = -13
  • 5x = -13 -7
  • 5x= -20
  • x = -20/5
  • x = -4
  • so the answer is x= -4
3 0
3 years ago
Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo
pav-90 [236]

Answer:

Probability distribution vector = \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)

Step-By-Step Explanation

If P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)  is the transition matrix for a Markov chain with two states.  

x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)  be the initial state vector for the population.

X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)  

X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)  

In the long run, the probability distribution vector Xm approaches the probability distribution vector \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right) .

This is called the steady-state (or limiting,) distribution vector.

4 0
3 years ago
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