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Cerrena [4.2K]
3 years ago
7

Simply each expression

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0
31.x^6
32.  a^35
33.  y^52
34.  w^315
35.  5^6
36.  23^56
37.  y^20
38.  16y^6
39.  64c^10
40. 9h^18
41.  y^12d^18
42. -3375h^27k^21
43.  k^51
44. 9x^5y^14z
45.  -128g^9h^9
46. 196a^20b^12c^6

Hope this will help!
stealth61 [152]3 years ago
3 0
Exponent rule : (a^b)^c = a^(b*c)

31. (x^2)^3 = x^(2 * 3) = x^6
32. (a^7)^5 = a^(7 * 5) = a^35
33. (y^13)^4 = y^(13 * 4) = y^52
34. (w^-21)^-15 = w^(-21*-15) = w^315
35. (5^2)^3 = 5^(2 * 3) = 5^6
36. (23^7)^8 = 23^(7 * 8) = 23^56
37. (-y^5)^4 = -y^(5 * 4) = y^20
38. (4y^3)^2 = 4^2 y^(3 * 2) = 16y^6
39. (8c^5)^2 = 8^2 c^(5 * 2) = 64c^10
40. (-3h^9)^2 = -3^2 h^(9 * 2) = 9h^18
41. (y^4d^6)^3 = y^(4 * 3)d^(6 * 3) = y^12d^18
42. (-15h^9k^7)^3 = -15^3h^(9*3)k^(7*3) = -3375h^27k^21
43. (k^9)^5(k^3)^2 = k(9 * 5)k^(3 * 2) = (k^45)(k^6) = k^51
44. (3y^6)^2 (x^5y^2z) = 3^2y^(6*2)(x^5y^2z) = 9y^12(x^5y^2z) =   
      9x^5y^14z
45. (4h^3)^2 (-2g^3h)^3 = 4^2h^(3*2) (-2^3g^(3*3)h^3) = 16h^6(-8g^9h^3)
      = -128g^9h^9
46. (14a^4b^6)^2 (a^6c^3)^2 = 14^2a^(4*2)b^(6*2) (a^(6*2)c^(3*2) =
      196a^8b^12(a^12c^6) = 196a^20b^12c^6




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\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}

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20 = -d + 6
Sphinxa [80]

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Write an equation of a line in slope intercept from given (6,4) (5,2)
Oksana_A [137]

Answer:

y=2x-8

Step-by-step explanation:

<em>Slope-Intercept Form </em>

<em>y=mx+b where y and x are variables, m is the slope, and b is the y-intercept</em>

<u>1. Find slope using the slope formula </u>\frac{y_{2}-y_{1} }{x_{2}-x_{1}}

\frac{2-4}{5-6} =\frac{-2}{-1} =2

You now have

y=2x+b

<u>2. Plug in one of the given points into the equation and solve for b</u>

y=2x+b

2=2(5)+b

2=10+b

-8=b

<u>Final Answer:</u>

y=2x-8

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2 years ago
A helicopter is hovering above a road at an altitude of 24 m. At a certain time, the distance
LuckyWell [14K]

Answer: 32.23°

Suppose the setpoint of a helicopter is A and that of a car is C and that of the road is B

The distance from the helicopter to the car and the road forms a right triangle

=> ΔABC is a right triangle at B

=> the angle of depression from  the helicopter from the car is ∠ACB

we have: ΔABC is a right triangle => sin ∠ACB = 24/45

=> m∠ACB = 32.23°

Step-by-step explanation:

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A​ hot-air balloon is 140 ft140 ft above the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) pass
luda_lava [24]

Answer:

Step-by-step explanation:

Given

Balloon velocity is 14 ft/s upwards  

Distance between balloon and cyclist is 140 ft

Velocity of motor cycle is 88 ft/s

After 10 sec  

motorcyclist traveled a distance of d_c=88\times 10=880 ft

Distance traveled by balloon in 10 s

d_b=14\times 10=140 ft

net height of balloon from ground =140+140=280 ft[/tex]

at t=10 s

distance between cyclist and balloon is z=\sqrt{280^2+880^2}

z=923.47 ft

now suppose at any time t motorcyclist cover a distance of x m and balloon is at a height of h m

thus z^2=(88t)^2+(14t+140)^2

differentiating w.r.t time

\Rightarrow z\frac{\mathrm{d} z}{\mathrm{d} t}=14\cdot \left ( 14t+140\right )+88\cdot \left ( 88t\right )

\Rightarrow at\ t=10 s

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{14\cdot \left ( 14t+140\right )+88\cdot \left ( 88t\right )}{z}

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{14\times 280+88^2\times 10}{923.471}

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{81,360}{923.471}=88.102\ ft/s

3 0
3 years ago
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