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Aleonysh [2.5K]

3 years ago

8

A zookeeper predicted the weight of a new baby elephant to be 253 pounds when it was born. The elephant actually weighed 285 pou

nds at birth. What was the percent error of the zookeeper's prediction? A. 88.77% B. 11.23% C. 12.65% D. 32%

1 answer:

spayn [35]3 years ago

7 0

Answer:

the answer is A

Step-by-step explanation:

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Which statement is true about the discontinuities of the function f(x) = x-5/3x^2-17x-28

o-na [289]

1) function f(x)

              x - 5
f(x) = ----------------
          3x^2 - 17x - 28

2) factor the denominator:

3x^2 - 17x - 28 = (3x + 4)(x - 7)

                        x - 5
=> f(x) = -----------------------
                (3x + 4) (x - 7)

3) Find the limits when x → - 4/3 and when x → 7

Lim of f(x) when x → - 4/3 = +/- ∞

=> vertical assymptote x = - 4/3

Lim of f(x) when x → 7 = +/- ∞

=> vertical assymptote x = 7

Answer: there are assympotes at x = 7 and x = - 4/3

6 0

3 years ago

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Mr. snorkel drove 169 miles in 3 h 30 min. find the rate in feet per minute

AVprozaik [17]

169 miles * 5280 ft/ mile = 892320 ft

3 hours * 60 minutes/1 hr = 180 minutes

3 hrs 30 minutes = 180 minutes + 30 minutes = 210 minutes

169 miles/ 3 hrs 30 minutes = 892320 ft/ 210 minutes = 4249.1 ft/ minutes

3 0

3 years ago

HELP I NEED HELP ASAP

lilavasa [31]

Answer:

I think it its

Step-by-step explanation:

C if its wrong sorry

8 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em /> $\displaystyle L = \sqrt{4kt - p}$

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, <em>add p to both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, <em>divide 4t by both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have <em>changed</em> the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

2 years ago

What’s 5/9 times 6?????????????????

Ksenya-84 [330]

Answer:

3.33333333333

Step-by-step explanation:

7 0

2 years ago

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