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boyakko [2]
4 years ago
10

Wayne Williams was a suspect in the murder of a number of African-American young men and boys, but was only convicted in two cas

es. His conviction was based on fiber samples found on victim's bodies that matched carpet in William's home and hair samples that were consistent with William's hair. Many years later, DNA testing confirmed that the hair matched Wayne William's hair with 98% accuracy. Why wasn't the DNA testing completely conclusive?
A)an insufficient number of hairs were found
B) William's had a twin who lived in the area
Eliminate
C) the root of the hair follicle wasn't attached
D) William's hair was identical to the victim's hair
SAT
1 answer:
s2008m [1.1K]4 years ago
6 0
The answer is C.
http://www.cnn.com/2010/CRIME/06/09/williams.dna.test/
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\begin{array}{cccccc}{Mean} & {1.5} & {2} & {2.5} & {3} & {3.5}\ \\ {Probability} & {\frac{1}{6}} & {\frac{1}{6}} & {\frac{1}{3}} & {\frac{1}{6}} & {\frac{1}{6}}\ \end{array}

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Required

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\begin{array}{cccccccccccc}{Selection} & {(1,2)} & {(1,3)} & {(1,4)} & {(2,1)} & {(2,3)} & {(2,4)}& {(3,1)} & {(3,2)} & {(3,4)} & {(4,1)} & {(4,2)} & {(4,3)} \ \\ {Mean} & {1.5} & {2} & {2.5} & {1.5} & {2.5} & {3} & {2} & {2.5} & {3.5} & {2.5} & {3} & {3.5}\ \end{array}

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P(2) \to \frac{2}{12} \to \frac{1}{6}\\

P(2.5) \to \frac{4}{12} \to \frac{1}{3}\\

P(3) \to \frac{2}{12} \to \frac{1}{6}\\

P(3.5) \to \frac{2}{12} \to \frac{1}{6}

So, the table of sampling distribution is:

\begin{array}{cccccc}{Mean} & {1.5} & {2} & {2.5} & {3} & {3.5}\ \\ {Probability} & {\frac{1}{6}} & {\frac{1}{6}} & {\frac{1}{3}} & {\frac{1}{6}} & {\frac{1}{6}}\ \end{array}

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