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4 years ago

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Ligers are a cross between lions and tigers. They exist only in zoos because lions and tigers do not live together in the wild.

Which is a reason why lions and tigers are considered separate species?

2 answers:

Tatiana [17]4 years ago

8 0

Answer:

Ligers can not reproduce :))

Explanation:

Ivanshal [37]4 years ago

7 0

They look different, they have different lifestyles, they vocalize differently, and they generally live on different continents.

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Categorize each statement as true or false. The SI V-Scope is a virtual microscope program which simulates the use of a compound

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The SI V-Scope is indeed a virtual microscope program that can stimulate the use of a compound light microscope so this is <u>TRUE</u>.

<h3>What is a SI V-Scope?</h3>

The SI V-Scope stands for a Science Interactive and then Virtual scope which is used simulate the way that a compound light microscope works.

These microscopes are very useful because they help people who don't have a physical microscope to access microscopes wherever they are.

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2 years ago

Which represents the copernican model that is most similar to that of aristarchus?

jeyben [28]

The Copernican model that is most similar to that of Aristarchus is where the solar system shows the planets in their orbits around the sun in the order: Mercury, Venus, Earth with Moon, Mars, Jupiter, Saturn.

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However, Copernicus later erased this reference, and Aristarchus' theory was not mentioned in the book published by him. Copernicus His model is the system of planetary motion maintained by Copernicus, in which the earth revolves once in a day and around the sun once in his year, while the other planets also has an orbit centered near the sun.

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1 year ago

A longitudinal wave is observed to be moving along a slinky

Korolek [52]

Explanation:

A longitudinal wave is composed of compressions and rarefactions. An example of a lomgitudinal wave is sound waves. It's a type of wave thay moves parrelel to axis.

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2 years ago

Why did Maggie not have flood insurance? Check all that apply. Storms in her region are highly unlikely. She wanted to pay for r

tamaranim1 [39]

here are the reasons why Maggie did not have a flood insurance.

C. She felt she needed to save money.

D. She may have misunderstood her basic homeowners policy.

E. Her expenses were already high before paying for insurance.

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The passage also said that there were months that the amount that she had was hardly enough to take care of basic needs.

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3 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

<em>The proportion of Good TV set is 0.67</em>
<em>The number of ways of selecting 5 from 6 TV sets is 6</em>
<em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

<u>(d) The sampling distribution</u>

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

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3 years ago