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oksian1 [2.3K]
4 years ago
9

A random sample of 18 graduates of a certain secretarial school typed an average of 80.6 words per minute with a standard deviat

ion of 7.2 words per minute. Assuming a normal distribution for the number of words typed per​ minute, compute the 95​% prediction interval for the next observed number of words per minute typed by a graduate of the secretarial school.
Mathematics
1 answer:
insens350 [35]4 years ago
7 0

Answer: ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 80.6 words per minute

Standard deviation r = 7.2

Number of samples n = 18

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

80.6+/-1.96(7.2/√18)

80.6+/-1.96(1.697056274847)

80.6 +/- 3.33

= ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

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What percent is represented by the diagram
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kari74 [83]

The graph that shows the solution to the system of inequalities is: C (see the image attached below).

<h3>How to Determine the Graph of the Solution to a System of Inequalities?</h3>

Given the following systems of inequalities:

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Below are the features of the graph that represents a solution to the system of inequalities:

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8 0
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3sweaters->$44.99

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in Youngstown, the population reached 4420 people in 1993. in 1998 the population was 5600 residents. what was the population in
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