Question

Cedric and doug each had an equal amount of money. After cedric spent $35 and doug spent $28, the ratio of cedrics money to dougs money was 2:3. How much money did each boy habe at first?

Answer 1

Answer:

Each of them had $49 at first.

Step-by-step explanation:

Given:

Cedric and Doug each had an equal amount of money.

Let the number of money they had at first be x

Cedric spent = $35

Doug spent = $28

Cedric Money left = $x-35$

Doug Money left = $x-28$

the ratio of Cedric money to Doug money was 2:3

Hence the expression can be made as;

$\frac{x-35}{x-28}=\frac{2}{3}$

Now by cross multiplication method we get;

$3(x-35)=2(x-28)$

Now we will use distributive property to elaborate the same;

$3x-105=2x-56$

Combining common terms we get;

$3x-2x=105-56$

Using Subtraction property we get;

$x= 49$

Hence $49 they each had at first.