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uranmaximum [27]
4 years ago
14

X and Y are continuous values, both measured to 2 significant figures. X=230 and Y=400. work out the greatest possible value of

X/Y^2.
(this is on an upper and lower bounds sheet)
Mathematics
1 answer:
kirill115 [55]4 years ago
8 0
"Two significant figures" means that a digit after the second one could actually be anything ... it wasn't measured. 'X' could be anything from 230 to 239. 'Y' could be anything from 400 to 409. The greatest possible value of that fraction is. (239)/(409 squared) .
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Decomponha os seguintes números a) 1.585 = b) 1.059= c) 2.440 d) 5.329 e) 8.801 f) 9.999 g) 3.718 h) 6.840 i) 7.504 j) 5.225 1)
vlada-n [284]

Answer:

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

Step-by-step explanation:

A medida que nos alejamos del punto decimal, el número de ceros aumenta y el dígito se mueve hacia la derecha.

Los valores después del decimal se denominan décimas, centésimas y milésimas.

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

The values after the decimal are called tenths hundredths and thousandths

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3 years ago
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Anni [7]
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Step-by-step explanation:

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