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4 years ago

10

Did I do this right? #15 ?

1 answer:

Lelu [443]4 years ago

6 0

Answer:

No you didn't the answer is -6x squared + 15x

Step-by-step explanation:

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starting at home, nadia traveled uphill to the grocery store for 30 minutes at just 4 mph. she then traveled back home along the

ankoles [38]

Distance from home to store = 4 * 0.5 = 2 miles.
Time taken to return home = (2/12) * 60 =10 minutes.
Total distance traveled = 2 * 2 = 4 miles.
Total time taken = 30 + 10 = 40 minutes.
Average speed for entire trip = total distance / total time in hours.
$Average\ speed=\frac{4}{\frac{40}{60}}=\frac{4\times60}{60}=6\ mph$

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4 years ago

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Find the surface area of the cylinder. Round to the nearest whole number.

natulia [17]

Answer:

I think it is 730

Step-by-step explanation:

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3 years ago

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Can a vector have a component greater than the vector's magnitude ?<br>

Mars2501 [29]

Answer: No, it can never be greater. At most it can be equal though.

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3 years ago

The line AB has midpoint (2,5).<br> A has coordinates (1, 2).<br> Find the coordinates of B.

Gekata [30.6K]

Answer:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

Step-by-step explanation:

For this case we know that the midpoint for the segment AB is (2,5)

And we know that the coordinates of A are (1,2)

We know that for a given segment the formulas in order to find the midpoint are given by:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

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4 years ago

HELP ASAP PLEASE Which is the correct way to model the equation 5 x + 6 = 4 x + (negative 3) using algebra tiles? 5 positive x-t

vichka [17]

Play10x9 than it =90

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3 years ago

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