Given :
Set of x-intercepts {-3,1,7},
point through which it passes (-2,54)
Now,
Step 1: Substitute value of x intercepts in equation,
, we get,

... equation (1)
Step 2: substitute x an y with the point through which it passes,


∴ 
Step 3: Now, substituting value of a in equation (1), we have

(Requited cubic equation)
Given:
Equation of line
.
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as

Slope of line is



Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is


![[\because m_1=\dfrac{7}{4}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20m_1%3D%5Cdfrac%7B7%7D%7B4%7D%5D)
Now, the slope of perpendicular line is
and it goes through (-21,2). So, the equation of line is






Therefore, the required equation in slope intercept form is
.