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Ber [7]
3 years ago
5

What is 804,006 in word form

Mathematics
2 answers:
andreev551 [17]3 years ago
3 0
Eight hundred and four thousand and six     is the written out word form of the number 804,006.
makvit [3.9K]3 years ago
3 0
Eight hundred thousand six
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prohojiy [21]

Given :

Set of x-intercepts {-3,1,7},

point through which it passes (-2,54)

Now,

Step 1: Substitute value of x intercepts in equation, y=a(x-p)(x-q)(x-r), we get,

y=a(x-(-3))(x-1)(x-7)

y= a(x+3)(x-1)(x-7)               ... equation (1)

Step 2: substitute x an y with the point through which it passes,

54=a((-2)+3)((-2)-1)((-2)-7)

54 = 27a

∴ a=2

Step 3: Now, substituting value of a in equation (1), we have

y=(2x+6)(x^{2} -8x+7)

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Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
nlexa [21]

Given:

Equation of line 7x-4y=-12.

To find:

The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

7x-4y+12=0

Slope of line is

\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

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m_1=\dfrac{7}{4}

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

m_1m_2=-1

m_2=-\dfrac{1}{m_1}

m_2=-\dfrac{4}{7}           [\because m_1=\dfrac{7}{4}]

Now, the slope of perpendicular line is m_2=\dfrac{4}{7} and it goes through (-21,2). So, the equation of line is

y-y_1=m_2(x-x_1)

y-2=-\dfrac{4}{7}(x-(-21))

y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

y-2=-\dfrac{4}{7}x-12

y=-\dfrac{4}{7}x-12+2

y=-\dfrac{4}{7}x-10

Therefore, the required equation in slope intercept form is y=-\dfrac{4}{7}x-10.

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Rewrite log; x = 4 in exponential form.
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Answer:

Step-by-step explanation

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