In the given graph point B is a relative maximum with the coordinates (0, 2).
The given function is 
.
In the given graph, we need to find which point is a relative maximum.
<h3>What are relative maxima?</h3>
The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.
In the graph, the maximum point is (0, 2).
Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).
To learn more about the relative maximum visit:
brainly.com/question/2321623.
#SPJ1
Simplifying it would make it 3/4b^2. I can't write it down the correct way, but it's three over four times b squared. Unless it's a square root, then things would be different.
3x + xy^2 + 5x - 2xy ok so once you can decode the sentence this is what it will look like. First you add the common facts which are 3x and 5x which = 8x ok so now we have 8x + xy^2 - 2xy so then I believe you cant do anything after that because there will be no more common factors hey can you tell me if I am write if you have already had turn this in please hope this helps
Answer: 480 units^2
IN DEPTH EXPLANATION TO HELP YOU FOR FUTURE PROBLEMS:
Front:
b*h/2 = sa
12*5/2 = 30
Front = 30 units^2
Back:
b*h/2 = sa
12*5/2 = 30
Back = 30 units^2
Right:
w*l = sa
14*13 = 182 units^2
Right: 182 units*2
(figures out the length by using
pythagorean theorem)
Left:
w*l = sa
5*14 = 70 units^2
Left: 70 units^2
Bottom:
w*l = sa
12*14 = 168 units^2
ADD ALL THE UNITS:
168 + 70 + 182 + 30 + 30 = 480
We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer isthe length is (g+10)
