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Komok [63]
3 years ago
14

How to find the missing values for each 45,45,90 o 30,60,90 triangle

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0
All three numbers have to have a equal multiple.
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The function C(x) = 25x + 50 represents the labor cost (in dollars) for Certified Remodeling to build a deck, where x is
Whitepunk [10]

Answer:

  • Master Remodeling

Step-by-step explanation:

<em>Original question is attached</em>

<h3>Option 1</h3>
  • C(x) = 25x + 50
  • C(8) = 25*8 + 50 = $250
<h3>Option 2</h3>
  • As per table, the rate of change is $30 per 2 hours.
  • So 8 hours will cost
  • $190 + $30 = $220

As we see the second option is cheaper so we should hire the Master Remodeling

5 0
3 years ago
Combine like terms to create an equivalent expression.
Lelu [443]

Answer:

\frac{1}{6} p - \frac{4}{5}

Step-by-step explanation:

collect like terms

- \frac{2}{3} p + \frac{5}{6} p + \frac{1}{5} - 1

= - \frac{2(2)}{2(3)} p + \frac{5}{6} p + \frac{1}{5} - \frac{5}{5}

= - \frac{4}{6} p + \frac{5}{6} p - \frac{4}{5}

= \frac{1}{6} p - \frac{4}{5}

5 0
2 years ago
Help will give branliest
Daniel [21]

Answer:

They make heart shapes! hearts look like <3

6 0
3 years ago
Calculus A hard problem help please
dexar [7]
∑x = 1 + 2 + 3 + 4 + 5 + 6 = 21
∑y = 8 + 3 + 0 + 1 + 2 + 1 = 15
∑x^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
∑y^2 = 64 + 9 + 0 + 1 + 4 + 1 = 79
∑xy = 8 + 6 + 0 + 4 + 10 + 6 = 34

r = (n∑xy - ∑x∑y)/(sqrt(n∑x^2 - (∑x)^2)*sqrt(n∑y^2 - (∑y)^2)) = (6(34) - 21(15))/(sqrt(6(91) - (21)^2)*sqrt(6(79) - (15)^2)) = (204 - 315)/(sqrt(546 - 441)*sqrt(474 - 225)) = -111/(sqrt(105)*sqrt(249)) = -111/(10.25*15.78) = -111/161.7 = -0.68

3 0
3 years ago
Read 2 more answers
Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3
KatRina [158]

Answer:

<h2>B. x = -1, x = -3, y = 0</h2>

Step-by-step explanation:

g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}

4 0
4 years ago
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