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galina1969 [7]
3 years ago
13

Which linear equation in two variables has a graph that passes through the points (3, –5) and (–7, 13)?

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

Option B. y+5=-\frac{9}{5}(x-3)

Step-by-step explanation:

step 1

Find the slope m

we have the points

(3, -5)\ and\ (-7, 13)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{13+5}{-7-3}

m=\frac{18}{-10}

Simplify

m=-\frac{9}{5}

step 2

Find the equation of the line in point slope form

we know that

The linear equation in point slope form is equal to

y-y1=m(x-x1)

we have

m=-\frac{9}{5}

(x1,y1)=(3,-5)

substitute

y-(-5)=-\frac{9}{5}(x-3)

y+5=-\frac{9}{5}(x-3)

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