Question

Find the first, fourth, and eighth terms of the sequence.

Answer 1

Answer:

-5, -40, -640

Step-by-step explanation:

$a(n)=-5\cdot2^{n-1}\\\\\text{put n = 1, n = 4 and n = 8 to the expression:}\\\\a(1)=-5\cdot2^{1-1}=-5\cdot2^0=-5\cdot1=-5\\\\a(4)=-5\cdot2^{4-1}=-5\cdot2^3=-5\cdot8=-40\\\\a(8)=-5\cdot2^{8-1}=-5\cdot2^7=-5\cdot128=-640$

Answer 2

Answer:

-5, -40, -640

Step-by-step explanation: