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alekssr [168]
3 years ago
14

An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir

cle that could fit in the square, like the drawing above.
How many more inches of silver wire did the artist use compared to copper wire? (remember that = 3.14)
Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

1.4 inches

Step-by-step explanation:

if I'm wrong please tell me right away I would like to help you good day.

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Write an algebraic expression for the word expression.
kolbaska11 [484]

Answer:

3 + x

Step-by-step explanation:

Sum means to add, so you would just add 3 and x (since they haven't given an actual number and only a variable).

3 0
3 years ago
ALGEBRA II HELP :/
elena-14-01-66 [18.8K]

Answer:

18

Step-by-step explanation:

f(x) = x³+4x²-8x-6

P(a) <=> P(x)

-2 | 1 4 -8 -6

|

| -2 -4 24

----------------------------

1 2 -12 18

4 0
3 years ago
roberto has 12 tiles. each tile is 1 square inch. he will arrange them into a rectangle and glue 1-inch stones around the edge.
LUCKY_DIMON [66]
To answer this you will need to determine which area made with the 12 square tiles would give the shortest perimeter.

Think of all the combinations to get 12 square inches
1x12, 2x6, and 3x4. The perimeters of these are 26 in, 16 in, and 14 in.

You should arrange your tiles using the 3 x 4 option. You would need 14 stones.
3 0
3 years ago
Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

8 0
3 years ago
Which of the following functions have a vertical asymptote for values of θ such that cos θ = 1? Select two answers.
valentina_108 [34]
Well costheta=1, at 0, 2pi,... 
knowing this we can exclude the first two as the are not undefined anywhere. 
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote 
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
3 0
3 years ago
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