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goldenfox [79]
4 years ago
9

How do you solve 7x+3y=0

Mathematics
1 answer:
jok3333 [9.3K]4 years ago
5 0
You're solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '-3Y' to each side of the equation.
7X + 3Y + -3Y = 0 + -3Y

Combine like terms:
3Y + -3Y = 0
7X + 0 = 0 + -3Y
7X = 0 + -3Y
Remove the zero:
7X = -3Y

<span>Divide each side by
'7'. X = -0.4285714286Y

</span><span>Simplifying
X = -0.4285714286Y</span>
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Solve for the missing side. Round to the nearest tenth.<br> х<br> 51°<br> 12
alisha [4.7K]

9514 1404 393

Answer:

  7.6

Step-by-step explanation:

The relevant relation is ...

  Cos = Adjacent/Hypotenuse

  cos(51°) = x/12

  x = 12·cos(51°) ≈ 7.552

  x ≈ 7.6

6 0
3 years ago
For a sequence an=3/n(n+1) what is the value of a 10
FrozenT [24]

Answer:

\large\boxed{a_{10}=\dfrac{3}{110}}

Step-by-step explanation:

Put <em>n = 10</em> to the equation a_n=\dfrac{3}{n(n+1)}

a_{10}=\dfrac{3}{10(10+1)}=\dfrac{3}{10(11)}=\dfrac{3}{110}

3 0
3 years ago
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vovangra [49]

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Slope=0

Step-by-step explanation:

8 0
4 years ago
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Is 0.35 grater than 300 mL
Sveta_85 [38]

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yes

Step-by-step explanation:

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6 0
3 years ago
Solve without a calculator log_4(20)-log_4(45)+log_4(144)
AfilCa [17]
Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144=                        (log_a b- log_a c=log_a  (b/c) )
log₄[(20*144)/45]=                             (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n     ⇔      4^n=64                (log_a x=n   ⇔ a^n=x)

4^n=4³      ⇒n=3                                 (64=4*4*4=4³)

Answer: log₄20-log₄ 45+log₄144=3

5 0
3 years ago
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