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2 years ago

4. Identify the domain and range of the relation {(2,4),(7,-9),(1,4),(3, -6), (8,0)}

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

4 0

Answer:

Domain: (2,7,1,3,8) Range: (4,-9,-6,0)

Step-by-step explanation:

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Tim has some marbles.

snow_tiger [21]

Answer:

Let x = the number of marbles Tim has

Let 2x = the number of marbles Sue has

x + 2x + 15 = 63

3x = 48

x = 16 marbles

Step-by-step explanation:

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2 years ago

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What is the quotient of the following division problem? 17374 ÷ 448 = ?

worty [1.4K]

B - 38 r350.
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3 years ago

The point (-3, -5) is on the graph of a function. Which equation must be true regarding the function?

Alecsey [184]

Answer:

f(- 3) = - 5

Step-by-step explanation:

Given the point (- 3, - 5)

where x = - 3 is the input and y = - 5 is the output

The function can be represented by

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3 years ago

Divide (x^3+2x^2-x-2) by (x-1)

Ymorist [56]

$\frac{x^3+2x^2-x-2}{(x-1)} =x^2+3x+2 \\ \\ x^3+2x^2-x-2= \\= x^2(x+2)-(x+2) \\ =(x+2)(x^2-1)=(x+2)(x-1)(x+1) \\ \\ \frac{x^3+2x^2-x-2}{(x-1)} = \frac{(x+2)(x-1)(x+1)}{x-1} =(x+2)(x+1)=x^2+3x+2$

7 0

3 years ago

What is the length of side a?

Bad White [126]

$\huge \bf༆ Answer ༄$

According to given figure, The Triangle BDC is a right angled Triangle (Angle D = 90°)

So, we can apply Pythagoras theorem to find the Side a (Hypotenuse)

Now, let's solve ~

$\sf \: BD {}^{2} + CD {}^{2} = BC {}^{2}$

$\sf4 {}^{2} + {3}^{2} = {a}^{2}$

$\sf16 + 9 = {a}^{2}$

$\sf \: a {}^{2} = 25$

$\sf \: a = \sqrt{25}$

$\sf \: a = 5 \: units$

Therefore, Length of side a is 5 units ~

6 0

2 years ago