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erastovalidia [21]
3 years ago
13

A restaurant offers three specials. a total of 40 of special a is order, 60 of special b, and 20 of special

Mathematics
1 answer:
Lina20 [59]3 years ago
8 0
I think 18 but i dont know

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Show me how to do the equation 6=z÷14​
polet [3.4K]

Answer:

\Huge \boxed{Z=84}

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation. Remember to solve this problem, multiplication property of equality is multiply both sides of an equation the same number doesn't change the equation.

First, switch sides.

\displaystyle \frac{z}{14}=6

Next, multiply 14 from both sides.

\displaystyle \frac{14z}{14}=6*14

Solve.

\displaystyle 6*14=84

Therefore, the correct answer is z=84.

8 0
4 years ago
Read 2 more answers
PLEASE I REALLY NEED HELP What differences are there on the graph of f(x)=2x to the graph of h(x)=2x-3?
Mila [183]

Answer:

The graph if h(x) =2x-3 will have the same slope, but placed lower on the graph, because it's y intercept is -3, while the y-int of f(x) is 0, which is higher up on the y axis

5 0
3 years ago
2. A recipe calls for 1/2 cup flour for every 3 cups
astra-53 [7]

Answer:

9 cups of milk is used

Step-by-step explanation:

1/2 + 1/2 + 1/2 = 1 1/2

3×3 = 9

6 0
3 years ago
An open box is made from a 20 cm x 3 cm piece of tin by cutting a square from each corner and folding up the edges. The area of
Marta_Voda [28]

Answer:

Length of the final sides: 6 cm and 16 cm

Step-by-step explanation:

The lengths of the sides of the original box are

L=20 cm\\W=10 cm

Later, a piece of tin is cut out from each corner; the piece cut out has the shape of the square: we can call the length of its generic side x. Therefore, the dimensions of the box will now be:

L'=L-2x\\W'=W-2x

We also know that the area is

A=96 cm^2

And the area can be written as product of length and width, therefore:

A=L'W'

So we find:

A=(L-2x)(W-2x)\\96=(20-2x)(10-2x)

Solving for x,

96=200-20x-40x+4x^2\\4x^2-60x+104=0\\\\x^2-15x-26=0

Which has two solutions:

x = 13 cm (this is larger than the initial length of the width, therefore we discard it)

x = 2 cm

So, the length of the new sides are

L=20-2x=20-2(2)=16 cm\\W=10-2x=10-2(2)=6 cm

7 0
3 years ago
Find the distance between the pair of points. (-16, 12) and (-22, -19).
NeTakaya
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}
d = \sqrt{[-22 - (-16)]^{2} + (-19 - 12)^{2}}
d = \sqrt{(-22 + 16)^{2} + (-31)^{2}}
d = \sqrt{(-6)^{2} + (-31)^{2}}
d = \sqrt{36 + 961}
d = \sqrt{997}
d \approx 31.57
8 0
3 years ago
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