Answer:
x-intercepts: (2,0), (4,0)
y-intercepts: (0,-8)

Explanation:
To find the x intercept(s), you must compute where y=0. So solve 0= -x^2 + 6x - 8. So, the x intercepts are: (2,0) and (4,0) since the solutions to the mentioned equation are x=2 and x=4. To find the y intercept(s) compute what is y when x=0. In this case, when x=0, y=-8. So the only y intercept is (0,-8).

5 0

3 years ago

Write an equation in standard form of the line that passes through the given point and has the given slope. (5,0) m=4/3

sveticcg [70]

$\text{The standard form of a line:}\ Ax+By=C$

$\text{The point-slope form:}$

$y-y_1=m(x-x_1)$

$\text{We have the point (5, 0) and the slope}\ m=\dfrac{4}{3}$

$\text{substitute:}\\\\y-0=\dfrac{4}{3}(x-5)\qquad|\text{use distributive property}\\\\y=\dfrac{4}{3}x-\dfrac{20}{3}\qquad|\text{multiply both sides by 3}\\\\3y=4x-20\qquad|\text{subtract 4x from both sides}\\\\-4x+3y=-20\qquad|\text{change the signs}\\\\\boxed{4x-3y=20}$

4 0

3 years ago

What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)

babymother [125]

Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109

Using AP, T(n)=15+11+7+....-129
T(n)=19-4n => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109

3 0

3 years ago