Answer:
f(x) > 0 over the interval
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from to -3, since between the values -4 and -3 the function adopts negative values.
16 on the y-axis, 0 on the x axis
1/6 plus 1/18, which equals to 2/9. Suppose we roll 4 on the first roll (the probability of rolling 4 is 1/12). On each successive roll the probability of rolling 7 is 1/6 and the probability of rolling 4 is 1/12.
[i.dk how this can help but if you got a 7 or 11 rolling on the first round you would probably win]
Answer:1331cm
Step-by-step explanation:vol=lbh
11*11*11cm=1331cm
Answer:
123
Step-by-step explanation:
s=-2
-15s^2-9(-5+s)
=-15s^2+45-9s
=-15s^2-9s+45
=15(-2)^2-9×(-2)+45
=15×4+18+45
=60+18+45
=123