What additional evidence supports the theory of plate?

How might a gene mutation be silent, with no observable effect on a cell or an organism? A. Codons are complementary to anticodo

steposvetlana [31]

Answer:

D. Many amino acids are encoded by multiple codons. A gene mutation that encodes the same amino acid would have no observable effect on the cell or the organism

Explanation:

If gene mutation does not change code (gene still encodes for the same amino acid), the same protein with its function will be produced. This is called synonymous mutation.

Silent mutations might also occur when codon is altered to produce an amino acid with similar function as previous (e.g. leucine to isoleucine) so that the function of protein is not significantly changed.

8 0

2 years ago

New milestones in environmental policy will most likely deal with long-term issues. Please select the best answer from the choic

alexandr1967 [171]

im pretty sure it is true

3 0

3 years ago

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Flock X Flock Y Flock Z Total Pieces of Food Eaten 57 153 90 Food Percentage* % % % Simulated Number of Birds in Flock for 2nd G

Zepler [3.9K]

Answer: The percentage would be 19%, 51% and 30%.

Explanation:

Since we have given that

Number of food eaten by X = 57

Number of food eaten by Y = 153

Number of food eaten by Z = 90

Total number of food eaten = $57+153+90=300$

So, Food percentage of flock X = $\dfrac{57}{300}\times 100=19\%$

Food percentage of flock Y = $\dfrac{153}{300}\times 100=51\%$

Food percentage of flock Z = $\dfrac{90}{300}\times 100=30\%$

Hence, the percentage would be 19%, 51% and 30%.

9 0

3 years ago

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Michelle was curious about her mother's blood type. Michelle knew that her own blood type was o,

babymother [125]

Blood type is determined by the I gene. IAIA and IAi determines A blood type. IBIB and IBi determines B blood type. ii determines 0 blood type. Michelle's mother must at least carry one recessive allele i.

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The blood type is determined by a gene, which is triallelic.

IA dominant over i. The person presents A type of antigens.

IB dominant over i. The person presents B type of antigens.

IA and IB are codominant. The person presents both types of antigens, A and B.

i is the recessive allele. The person does not present any antigen.

⇒ H0m0zyg0us dominant individuals IAIA, or heter0zyg0us Individuals IAi, will express the A blood type.

⇒ H0m0zyg0us dominant individuals IBIB, or heter0zyg0us Individuals IBi, will express the B blood type.

⇒ Individuals with h0m0zyg0us recessive genotype, ii will express the 0 blood type.

⇒ Individuals carrying IA and IB alleles will express the AB blood type.

To solve the problem, we will use this information.

We know that

Michelle is blood type 0

Father is blood type A

Brother and sister are blood type A

Mother??

⇒ If Michelle is blood type 0, then her genotype is ii. She must have received one recessive allele from her father and one from her mother.

⇒ This suggests that Michelle's father, who is blood type A, is heter0zyg0us IAi. He must have at least one dominant allele IA that determines his phenotype, and one i allele.

⇒ Michelle's brother and sisters are also type A. They might be either h0m0zyg0us dominant IAIA or heter0zyg0us IAi.

⇒ Michelle's mother should have at least one recessive allele i. She could be either IAi or IBi, or ii. There are three possible option for her genotype.

Let us make the Punnet squares to understand it better. We know the genotype of the father, but there are three options for the mother.

Option 1

Cross) father x mother

Parentals) IAi x IAi

Gametes) IA i IA i

Punnett square) IA i

IA IAIA IAi

i IAi ii

F1) 25% of the progeny is expected to be h0m0zyg0us dominant IAIA

50% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be h0m0zyg0us recessive ii

75% of the progeny is expected to be blood type A ⇒ IAIA and IAi ⇒ Sisters and brother

25% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Option 2

Cross) father x mother

Parentals) IAi x IBi

Gametes) IA i IB i

Punnett square) IA i

IB IBIA IBi

i IAi ii

F1) 25% of the progeny is expected to be IAIB

25% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be heter0zygus IBi

25% of the progeny is expected to be h0m0zyg0us recessive ii

25% of the progeny is expected to be blood type AB ⇒ IAIB

25% of the progeny is expected to be blood type A ⇒ IAi ⇒ Sisters and brother

25% of the progeny is expected to be blood type B ⇒ IBi

25% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Option 3

Cross) father x mother

Parentals) IAi x ii

Gametes) IA i i i

Punnett square) IA i

i IAi ii

F1) 50% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be h0m0zyg0us recessive ii

50% of the progeny is expected to be blood type A ⇒ IAi ⇒ Sisters and brother

50% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Despite the fact we can not determine for sure the mother's genotype, we know that she carries at least one recessive allele, which is why Michelle's blood type is 0.

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8 0

2 years ago

Apples as we know them today did not always exist. All apple varieties available to us today are derived from the wild relative

Vesnalui [34]

Answer:

The correct answer is letter D. Conventional breeding

Explanation:

In conventional genetic improvement a plant is crossed with another of the same species, with no incorporation of genes from another organism into the plant's genome, requiring repeated crossings until reaching the desired improved cultivar. Only in transgenics or genetic engineering are genes from another organism incorporated into the plant's genome.

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3 years ago

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