The speed of sound depends on the material the sound is passing through. Below is the approximate speed of sound (in feet per se
cond) for air, water and steel:
air: 1,100 feet per second
water: 4,900 feet per second
steel: 16,400 feet per second
Write a program that displays a menu allowing the user to select air, water, or steel. After the user has made a selection, he or she should be asked to enter the distance a sound wave will travel in the selected medium. The program will then display the amount of time it will take.
Menu. The menu should look exactly like this:
Select a medium:
1. Air
2. Water
3. Steel
air: 1,100 feet per second
water: 4,900 feet per second
steel: 16,400 feet per second
Write a program that displays a menu allowing the user to select air, water, or steel. After the user has made a selection, he or she should be asked to enter the distance a sound wave will travel in the selected medium. The program will then display the amount of time it will take.
Menu. The menu should look exactly like this:
Select a medium:
1. Air
2. Water
3. Steel
1 answer:
Answer:
The Java Program for the given problem is as below. Directly copy the code and run it on your machine.
Explanation:
Refer the Screenshots attached for the output.
import java.io.BufferedReader;
import java.io.InputStreamReader;
public class TheSpeedOfSound {
public static void main(String[] s)
{
String medium;
double distance;
double time;
try{
BufferedReader choice = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter one of the following: air, water, or steel: ");
medium = choice.readLine(); // reading input i.e. air, water or steel
//check for air water and steel
if (medium.equalsIgnoreCase("air") || medium.equalsIgnoreCase("water") || medium.equalsIgnoreCase("steel")){
System.out.println("Enter the distance the sound wave will travel: ");
distance = Double.parseDouble(choice.readLine()); // read distance value if it is air water or steel
switch (medium)
{
//if medium is air
case "air":
time = distance/1100;
System.out.print("It will take " + time + " seconds.");
break;
//if medium is water
case "water":
time = distance/4900;
System.out.print("It will take " + time + " seconds.");
break;
//if medium is steel
case "steel":
time = distance/16400;
System.out.print("It will take " + time + " seconds.");
break;
}
}
else{
System.out.print("Sorry, you must enter air, water, or steel.");
}
}
catch(Exception e){
e.printStackTrace();
}
}
}
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Answer:
C code for half()
#include<stdio.h>
void half(float *pv);
int main()
{
float value=5.0; //value is initialized
printf ("Value before half: %4.1f\n", value); // Prints 5.0
half(&value); // the function call takes the address of the variable.
printf("Value after half: %4.1f\n", value); // Prints 2.5
}
void half(float *pv) //In function definition pointer pv will hold the address of variable passed.
{
*pv=*pv/2; //pointer value is accessed through * operator.
}
- This method is called call-by-reference method.
- Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
- The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(), we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
- Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.
Output:
Output is given as image.
