Answer:
The area of the actual playground is 
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
let
z------> the scale factor
x------> the area of the actual playground
y-----> the area of the scale model of a playground
so
we have
substitute and solve for x
6g + 4(-5+4g) = 1 - g
6g - 20 + 16g = 1 - g
22g - 20 = 1 - g
22g + g = 1 + 20
23g = 21
g = 21/23 or 0.913043 in decimal form.
If you have any questions on how I got to this answer, please ask. :)
Answer:
It's not possible.
Step-by-step explanation:
It has two equals sign and an underscore. make sure yu have the right equation.
Answer:
$900
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year,
then, solving our equation
I = 5000 × 0.03 × 6 = 900
I = $ 900.00
The simple interest accumulated
on a principal of $ 5,000.00
at a rate of 3% per year
for 6 years is $ 900.00.
Answer:
The answer is below
Step-by-step explanation:
Mrs. Fielder decides to build a small snow shelter for her children to wait in before the school bus arrives in the morning. She has only enough wood for a total perimeter of 20 feet.
a. Make a table of all the whole number possibilities for the length and width of the shelter. Find the area of each shelter.
b. What dimensions should Mrs. Fielder choose to have the greatest area in her shelter?
c. What dimensions should Mrs. Fielder choose to have the least area in her shelter?
d. Township building codes require 3 square feet for each child in a snow shelter. Which shelter from part (a) will fit the most children? How many children is this? Explain your reasoning.
Solution:
a) Let W represent the width of the school shelter and let L represent the length of the school shelter. Therefore:
Perimeter of the school shelter = 2(length + breadth)
20 = 2(L + W)
L + W = 10
Also, the area of the school shelter = L * W
Length (ft) Width (ft) Area(ft²) = length * width
1 9 9
2 8 16
3 7 21
4 6 24
5 5 25
b) The shelter with a length of 5 ft and width of 5 ft has the largest area.
c) The shelter with a length of 1 ft and width of 9 ft has the least area.
d) The 4 by 6 ft shelter can hold 8 children (24 ft² / 3 ft² = 8) and the 5 by 5 ft shelter can hold 8 children with an extra space (25 ft² / 3 ft² = 8.33).
