The numbers are "x" and "y" Therefore, we can suggest this system of equations: x+y=10 ⇒x=10-y xy=-60 Solve this system of equations by substitution method. (10-y)y=-60 10y-y²=-60 y²-10y-60=0 Solve this square equation: y=[10⁺₋√(100+240)]/2=(10⁺₋2√85)/2=5⁺₋√85
We have two solutions: y₁=5-√85 ⇒x₁=10-(5-√85)=5+√85 y₂=5+√85 ⇒x₂=10-(5+√85)=5-√85