,,,Help Please.. Question in the file.

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

6 0

So hmmm there are 5pennies in a nickel, and 10pennies in a dime and 25pennies in a quarter

now, in $6.10, there are 610 pennies

n = amount of nickels coins
d = amount of dime coins
q = amount of quarter coins

so... we know, there are 5*n or 5n pennies in the nickels, and 10*d or 10d pennies in the dimes and 25*q or 25q in the quarter coins, and we know their sum is 610 pennies total, thus

5n + 10d + 25q = 610

now, there are 4 more "n" then "d", so whatever "d" is, "n" is 4 more than that
n = d + 4

and twice as many "q" than "n", so, whatever "n" is, then
q = 2n

$\bf 5n+10d+25q=610\implies n+2d+5q=122\qquad 
\begin{cases}
n=d+4\\
q=2n\\
------\\
q=2(d+4)\\
\qquad 2d+8
\end{cases}
\\\\\\
\boxed{d+4}+2d+5\left( \boxed{2d+8} \right)=122$

solve for "d", to see how many dimes are there

what about the nickels? well, n = d + 4
what about the quarters? well, q = 2d + 8

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Serga [27]

1) If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is $\frac{1}{6}$ .

If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is $\frac{3}{6}$ = $\frac{1}{2}$ .

<h3>Here are two more examples: </h3>

If a coin is flipped twice, determine the probability that it will land heads both times:

Favorable outcomes: 1 -- HH

Possible outcomes: 4 -- HH, HT, TH, TT

Thus, the probability that the coin will land heads both times is $\frac{1}{4}$ .

If Dan grabs one sock from a drawer containing 3 white socks, 4 blue socks, and 5 yellow socks, what is the probability that he will grab a white sock?

Favorable outcomes: 3 (3 white socks)

Possible outcomes: 12 (3 white socks + 4 blue socks + 5 yellow socks)

Thus, the probability that Dan will grab a white sock is $\frac{3}{12}$ = $\frac{1}{4}$ .